//依旧快速幂
a = 2147483647, b = [2,0,0]
var superPow = function(a, b) {
    if(a==1)return a
    let ans = 1
    let numB = Number(b.join(''))
    while(numB){
        if(numB%2){
            ans = ans*a
        }
        a*=a
        numB = Math.floor(numB/2)
    }
    return ans
};
console.log(superPow(a,b));
